python - Print only the characters below a specific word in a line -
i'm trying write script 2 different things: picks random word , causes "jump" out of line, , "turns" on word. turn, mean picks random word , prints same number of characters word beneath it, , nothing else, so:
this thing typing sdfas wertq wsvsd swefs
this mean making "jump" out of line:
thing typing
my problem cannot figure out how "print [x] number of characters under x"
here code, below:
import random import sys s = open('sonnets.txt') counting = 0 line in s: line.strip() randomint = random.randint(1,100) counting = counting+1 words = line.split() test = 1 if (randomint < 2*counting): if (len(words) > 0): r = random.choice(words) if r in line: ind = line.index(r) wordchoice = len(r) print ((" " * (ind))+r).upper() whitespace = wordchoice+2 newline = line.replace(r, (" " * whitespace)) print newline turn = random.choice(words) if turn in line: turncheck = true ind = line.index(turn) wordchoice = len(turn) print ((" " * (ind))+turn) foo = line[ind:ind+4] print ((" " * (ind))+foo) else: print line
the above code runs, succeeds in making text "jump". can creating column of words?
again, give appreciated. thank you!
txt='this thing typing' jumpword='thing' jumpind=txt.find(jumpword) newtxt=str(txt) if jumpind>=0: newtxt=newtxt.replace(jumpword," "*len(jumpword),1) newtxt=" "*jumpind+jumpword+'\n'+newtxt print newtxt
result:
thing typing
the word turning:
import random def randword(length,sourcelist): # random word: (move out of function if need keep same) rword=random.sample(sourcelist,1)[0] # length number of letters it. return "".join(map(lambda dummy:random.sample(rword,1)[0],range(length))) print txt # make 5 turns: in range(5): print " "*jumpind+randword(len(jumpword),txt.split())
result:
this thing typing iiiii aaaaa iiiii yngtt hthti
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