pointers - Unexpected C code output -

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this c code:

#include <stdio.h>   int main(){  int x[] = {6,1,2,3,4,5}; int *p=0; p =&x[0];   while(*p!='\0'){      printf("%d",*p);     p++; }  return 0;   }

when run output 612345-448304448336

what digits after minus sign , why code giving this?

the condition *p != '\0', same *p != 0, never met because array doesn't contain element of value 0, , overrun array bounds , step undefined behaviour.

instead, should control array range directly:

for (int const * p = x; p != x + sizeof(x)/sizeof(x[0]); ++p)  // or "p != x + 6" {     printf("%d", *p); }

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