c# - Compare XPath list to find the closest to another node? -

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i have following node

"/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[7]/p[1]/#text[1]"

how can figure out last 1 of these closest one?

"/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[4]/div[1]/img[1]" "/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[4]/div[3]/a[1]/img[1]" "/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[4]/div[3]/a[2]/img[1]" "/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[4]/div[5]/img[1]" "/html[1]/body[1]/div[1]/div[1]/div[3]/div[1]/div[5]/div[1]/img[1]"

it won't last one.

here's how got there:

protected string guessthumbnail(htmldocument document) {     htmlnode root = document.documentnode;     ienumerable<string> result = new list<string>();      htmlnode description = root.selectsinglenode(descriptionpredictivexpath);     if (description != null) // in case, predict relevant images ones closest description text node.     {         htmlnode node = description.parentnode;         while (node != null)         {             string path = string.concat(node.xpath, imagexpath);             node = node.parentnode;             ienumerable<htmlnode> nodes = root.selectnodesorempty(path);              // find image tag that's closest text node.             if (nodes.any())             {                 var xpaths = nodes.select(n => n.xpath);                 xpaths.tolist();                  // return closest             }         }     }     // figure other way      throw new notimplementedexception(); }

consider assigning "position in whole tree in depth-first order" each node. way comparing 2 nodes simple.

if can attach arbitrary data nodes - add directly. otherwise have dictionary of nodes position map.

note depending on how many times need comparison approach may slow you, should easy implement , measure it meats requirements.


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