ios5 - ios 5 UIWebView show rows from UITableView -
this week started learning ios coding i'm getting strange error have made little script witch have on main page list of names made uitableview , when select row it's open relative url, when load webpage goes wrong webpage have rows 'uitableview'.
did u know why it's generate kind of error?
that it's generate;

update have re-writed app proble still present, don't understand why show rows on webpage
in rootviewcontroller.m call webpage class
- (void) tableview:(uitableview *)tableview didselectrowatindexpath:(nsindexpath *)indexpath{    nsdictionary *game = [[self.sections valueforkey:[[[self.sections allkeys] sortedarrayusingselector:@selector(localizedcaseinsensitivecompare:)] objectatindex:indexpath.section]] objectatindex:indexpath.row];  [tableview deselectrowatindexpath:indexpath animated:yes]; //svanisce il blu   nslog(@"%@", [[self.games objectatindex:indexpath.row ] objectforkey:@"url"]); // funge  webpage *newweb = [[webpage alloc] init];  newweb.theurl = [nsurl urlwithstring:[game objectforkey:@"url"]];  [self.navigationcontroller pushviewcontroller:newweb animated:yes];   } that webpage.h
#import <uikit/uikit.h>  @interface webpage : uitableviewcontroller <uiwebviewdelegate> {      uiwebview *webview;     nsurl *theurl;  }  @property (nonatomic, retain) nsurl *theurl; @property (nonatomic, retain) uiwebview *webview;  @end and webpage.m
#import "webpage.h"  @implementation webpage  @synthesize theurl; @synthesize webview;  - (void)viewdidload {     [super viewdidload];      webview = [[uiwebview alloc] initwithframe:cgrectmake(0,0, self.view.bounds.size.width, self.view.bounds.size.height)];      webview.delegate = self;      webview.scalespagetofit = yes;      [webview loadrequest:[nsurlrequest requestwithurl:theurl]];      [self.view addsubview:webview];  }  @end 
it because webpage class derived uitableviewcontroller. instead derive uiviewcontroller.
eg
@interface webpage : uiviewcontroller <uiwebviewdelegate> {      uiwebview *webview;     nsurl *theurl;  } 
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